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[Bertrand BRATSCHI <address@hidden>]

I almost completed a plugin for Haskell, but I’m stuck with a problem involving string-replacement,
(due to the fact I’m very ignorant in Scheme).


I tried to modify (haskell-serialize lan t) by adding:

[1]  :  (string-replace s "\"" "''")  "\n")
In order to substitute two simple quotes character by on double quote character.
( That allowst the plugin can accept the definition of a string, like  : name = "blabla" )

I also tried the following :

[2]   :  (string-replace s "\n" "~")  "\n")
That is for interpreting multiline expressions, or some code with Haskell indentation.

Both [1] and [2] give the expected result when used alone, but I have no idea how to combinate them  (please have a look o lines 24-25 of file  init-haskell in attachment )

Regards,
Bertrand

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